5u^2=13u

Solution for 5u^2=13u equation:

5u^2=13u

We move all terms to the left:

5u^2-(13u)=0

a = 5; b = -13; c = 0;
Δ = b2-4ac
Δ = -132-4·5·0
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{169}=13$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-13}{2*5}=\frac{0}{10}
=0
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+13}{2*5}=\frac{26}{10}
=2+3/5
$